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ANSWER

hammett

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The answer HAMMETT has 5 possible clue(s) in existing crosswords.

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The word HAMMETT is NOT valid in any word game. (Sorry, you cannot play HAMMETT in Scrabble, Words With Friends etc)

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Definitions of hammett in various dictionaries:

noun - United States writer of hard-boiled detective fiction (1894-1961)

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Possible Crossword Clues
Creator of 65 Down
"The Maltese Falcon" novelist
Spade creator
Sam Spade creator
Sam Spade's creator

Last Seen in these Crosswords & Puzzles
Sep 3 2017 Newsday.com
Feb 23 2017 L.A. Times Daily
Apr 28 2015 L.A. Times Daily
Jan 1 2010 Wall Street Journal
Feb 15 2009 Newsday.com

Geographic Matches
Hammett, GEORGIA, UNITED STATES
Hammett, PENNSYLVANIA, UNITED STATES
Hammett, IDAHO, UNITED STATES

Hammett might be related to
The Hammett equation in organic chemistry describes a linear free-energy relationship relating reaction rates and equilibrium constants for many reactions involving benzoic acid derivatives with meta- and para-substituents to each other with just two parameters: a substituent constant and a reaction constant. This equation was developed and published by Louis Plack Hammett in 1937 as a follow-up to qualitative observations in a 1935 publication.The basic idea is that for any two reactions with two aromatic reactants only differing in the type of substituent, the change in free energy of activation is proportional to the change in Gibbs free energy. This notion does not follow from elemental thermochemistry or chemical kinetics and was introduced by Hammett intuitively.The basic equation is: * * * * log * ⁡ * * * K * * K * * 0 * * * * * = * σ * ρ * * * {\displaystyle \log {\frac {K}{K_{0}}}=\sigma \rho } * * relating the equilibrium constant, K, for a given equilibrium reaction with substituent R and the reference K0 constant when R is a hydrogen atom to the substituent constant σ which depends only on the specific substituent R and the reaction constant ρ which depends only on the type of reaction but not on the substituent used. * The equation also holds for reaction rates k of a series of reactions with substituted benzene derivatives: * * * * log * ⁡ * * * k * * k * * 0 * * * * * = * σ * ρ * . * * * {\displaystyle \log {\frac {k}{k_{0}}}=\sigma \rho .} * * In this equation k0 is the reference reaction rate of the unsubstituted reactant, and k that of a substituted reactant. * A plot of log(K/K0) for a given equilibrium versus log(k/k0) for a given reaction rate with many differently substituted reactants will give a straight line.

Hammett might be related to

The Hammett equation in organic chemistry describes a linear free-energy relationship relating reaction rates and equilibrium constants for many reactions involving benzoic acid derivatives with meta- and para-substituents to each other with just two parameters: a substituent constant and a reaction constant. This equation was developed and published by Louis Plack Hammett in 1937 as a follow-up to qualitative observations in a 1935 publication.The basic idea is that for any two reactions with two aromatic reactants only differing in the type of substituent, the change in free energy of activation is proportional to the change in Gibbs free energy. This notion does not follow from elemental thermochemistry or chemical kinetics and was introduced by Hammett intuitively.The basic equation is:
*
*
*
* log
* ⁡
*
*
* K
*
* K
*
* 0
*
*
*
*
* =
* σ
* ρ
*
*
* {\displaystyle \log {\frac {K}{K_{0}}}=\sigma \rho }
*
* relating the equilibrium constant, K, for a given equilibrium reaction with substituent R and the reference K0 constant when R is a hydrogen atom to the substituent constant σ which depends only on the specific substituent R and the reaction constant ρ which depends only on the type of reaction but not on the substituent used.
* The equation also holds for reaction rates k of a series of reactions with substituted benzene derivatives:
*
*
*
* log
* ⁡
*
*
* k
*
* k
*
* 0
*
*
*
*
* =
* σ
* ρ
* .
*
*
* {\displaystyle \log {\frac {k}{k_{0}}}=\sigma \rho .}
*
* In this equation k0 is the reference reaction rate of the unsubstituted reactant, and k that of a substituted reactant.
* A plot of log(K/K0) for a given equilibrium versus log(k/k0) for a given reaction rate with many differently substituted reactants will give a straight line.

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