Welcome to Anagrammer Crossword Genius! Keep reading below to see if bigram is an answer to any crossword puzzle or word game (Scrabble, Words With Friends etc). Scroll down to see all the info we have compiled on bigram.
bigram
Searching in Crosswords ...
The answer BIGRAM has 5 possible clue(s) in existing crosswords.
Searching in Word Games ...
The word BIGRAM is NOT valid in any word game. (Sorry, you cannot play BIGRAM in Scrabble, Words With Friends etc)
Searching in Dictionaries ...
Definitions of bigram in various dictionaries:
noun - a word that is written with two letters in an alphabetic writing system
BIGRAM - A bigram or digram is a sequence of two adj acent elements from a string of tokens, which are typically letters, syllables, or words. A bigram is an n...
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Keep reading for additional results and analysis below.
Possible Crossword Clues |
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EG, e.g |
Puzzlemaking term for a two-letter unit |
Letter pair |
Two-letter cluster |
Two-letter pair |
Last Seen in these Crosswords & Puzzles |
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Nov 20 2018 Jonesin' |
Jan 8 2012 The Washington Post |
May 4 2008 Boston Globe |
Mar 16 2007 Wall Street Journal |
May 28 2006 L.A. Times Magazine |
Bigram description |
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A bigram or digram is a sequence of two adjacent elements from a string of tokens, which are typically letters, syllables, or words. A bigram is an n-gram for n=2. The frequency distribution of every bigram in a string is commonly used for simple statistical analysis of text in many applications, including in computational linguistics, cryptography, speech recognition, and so on. * Gappy bigrams or skipping bigrams are word pairs which allow gaps (perhaps avoiding connecting words, or allowing some simulation of dependencies, as in a dependency grammar). * Head word bigrams are gappy bigrams with an explicit dependency relationship. * Bigrams help provide the conditional probability of a token given the preceding token, when the relation of the conditional probability is applied:* * * * P * ( * * W * * n * * * * | * * * W * * n * − * 1 * * * ) * = * * * * P * ( * * W * * n * − * 1 * * * , * * W * * n * * * ) * * * P * ( * * W * * n * − * 1 * * * ) * * * * * * {\displaystyle P(W_{n}|W_{n-1})={P(W_{n-1},W_{n}) \over P(W_{n-1})}} * * That is, the probability * * * * P * ( * ) * * * {\displaystyle P()} * of a token * * * * * W * * n * * * * * {\displaystyle W_{n}} * given the preceding token * * * * * W * * n * − * 1 * * * * * {\displaystyle W_{n-1}} * is equal to the probability of their bigram, or the co-occurrence of the two tokens * * * * P * ( * * W * * n * − * 1 * * * , * * W * * n * * * ) * * * {\displaystyle P(W_{n-1},W_{n})} * , divided by the probability of the preceding token. |